(4/7)x^2+2x-5=0

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Solution for (4/7)x^2+2x-5=0 equation: 



(4/7)x^2+2x-5=0



Domain of the equation: 7)x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/7)x^2+2x-5=0

We add all the numbers together, and all the variables

2x+(+4/7)x^2-5=0

We multiply all the terms by the denominator


2x*7)x^2+(-5*7)x^2+4=0

We add all the numbers together, and all the variables

2x*7)x^2+(-35)x^2+4=0

Wy multiply elements

14x^2-35)x^2+4=0

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